Step-by-step calculation:

• Total system discharge = $150\text{ m}^3/\text{hr} = 150,000\text{ L/hr}$.
• Dripper discharge $q_e = 8\text{ L/hr}$.
• Total number of drippers/emitters in the system:
  $$N_{\text{emitters}} = \frac{150,000}{8} = 18,750$$
• Daily plant water requirement = $15\text{ L/day}$.
  With 1 hour daily operating time, each emitter provides 8 L. Thus, emitters needed per plant = $\frac{15}{8 \times 1} = 1.875 \approx 2\text{ emitters/plant}$.
• Total number of plants supported:
  $$N_{\text{plants}} = \frac{18,750}{2} = 9,375\text{ plants}$$
  6. With plant spacing of $1\text{ m} \times 1\text{ m} = 1\text{ m}^2$ per plant, the total area of the field is:
  $$\text{Area} = 9,375 \times 1\text{ m}^2 = 9,375\text{ m}^2$$