- Proportional and Neyman Allocation Calculations:
- Total population size: $N = N_1 + N_2 = 300 + 200 = 500$
- Total sample size: $n = 100$
- Proportional Allocation:
- Strata sample sizes are allocated in direct proportion to strata population sizes ($n_i = n \frac{N_i}{N}$):
$$n_1 = 100 \times \frac{300}{500} = 60$$
$$n_2 = 100 \times \frac{200}{500} = 40$$
- Neyman (Optimum) Allocation:
- Strata standard deviations: $S_1 = \sqrt{25} = 5$, and $S_2 = \sqrt{100} = 10$
- Weighted products:
$$N_1 S_1 = 300 \times 5 = 1500$$
$$N_2 S_2 = 200 \times 10 = 2000$$
$$\sum N_i S_i = 1500 + 2000 = 3500$$
- Neyman sample allocations ($n_i = n \frac{N_i S_i}{\sum N_i S_i}$):
$$n_1 = 100 \times \frac{1500}{3500} = \frac{150}{3.5} \approx 42.86 \approx 43$$
$$n_2 = 100 \times \frac{2000}{3500} = \frac{200}{3.5} \approx 57.14 \approx 57$$
- Summary:
- Stratum 1: Proportional = 60, Neyman = 43
- Stratum 2: Proportional = 40, Neyman = 57
- Conclusion: Matches Option 2.
Correct option: (2) Option 2