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ICAR JRF Computer Application 29 Jun 2024Shift 1
MCQ (Single Correct) +4 −1
Of the 36 accounts drawn randomly from a very large number of accounts in a certain bank, 12 had a deposit of less than Rs. 1500. The estimated standard error for the estimate of the proportion of accounts having a deposit of less than Rs. 1500 is
  • Standard Error of Estimated Proportion:
  • Sample size: $n = 36$
  • Number of accounts with deposit < Rs. 1500: $x = 12$
  • Sample proportion: $p = \frac{x}{n} = \frac{12}{36} = \frac{1}{3}$, and $q = 1 - p = \frac{2}{3}$
  • In simple random sampling from a very large population, the unbiased estimator of the variance of the sample proportion is:
$$s_p^2 = \frac{p(1 - p)}{n - 1} = \frac{\frac{1}{3} \times \frac{2}{3}}{36 - 1} = \frac{2/9}{35} = \frac{2}{315}$$
  • The estimated standard error ($SE$) is the square root of the variance:
$$SE(p) = \sqrt{\frac{p(1 - p)}{n - 1}} = \sqrt{\frac{2}{315}}$$
  • Conclusion: The estimated standard error is $\sqrt{\frac{2}{315}}$ (Option 4).

Correct option: (4) on

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