Which one of the following is not typically provided by Source... | Agrigyan

• SQL Query Group By Evaluation:
• Natural join on Roll-No matches all student records with performance records:
• Ramesh (18CS101): Marks 60 + 65 = 125
• Mukesh (18CS102): Marks 80 + 75 = 155
• Ramesh (18CS103): Marks 85 + 70 = 155
• The query groups by S.Name (GROUP BY S.Name):
• Distinct values in S.Name across the join are 'Mukesh' and 'Ramesh' (two distinct student names).
• Group 'Mukesh': Sum = 155 (1 row)
• Group 'Ramesh': Combines both 18CS101 and 18CS103 $\implies$ Sum = $125 + 155 = 280$ (1 row)
• Therefore, the query returns exactly 2 rows.
• Conclusion: The number of rows returned is 2 (Option 3).

Correct option: (3) 2

• Language Generated by Context-Free Grammar:
• Productions for $X$:
• $X \to aX \mid Xb \mid a \mid b$
• $X$ generates any non-empty string consisting of combinations of $a$'s and $b$'s: $L(X) = (a + b)^+ = a^(a + b)b^$.
• Productions for $S$:
• $S \to aSb \mid X$
• $S$ wraps an equal number of $a$'s on the left and $b$'s on the right around string generated by $X$ ($a^n X b^n, n \ge 0$).
• Combining them yields any string containing at least one $a$ or $b$ with leading $a$'s and trailing $b$'s: $a^(a + b)b^$.
• Conclusion: The language generated is a(a + b)b (Option 2).

Correct option: (2) The language generated by Gis a’(a + b)b*

• Regular Expression from DFA Transition Analysis:
• From start state $s$:
• single transition on input 1 reaches the accepting state $p$.
• At accepting state $p$:
• Reading 0 loops back to $p$.
• Reading 11 transitions through state $q$ and loops back to $p$.
• Any repetition of 0 and 11 keeps the machine in accepting state $p$.
• The complete regular expression for strings driving the DFA from $s$ to $p$ is:

• Conclusion: 1(0 + 11)* (Option 3).

Correct option: (3) 1(0+ 11)"