5
ICAR JRF Fish Genetics And Breeding 29 Jun 2024Shift 1
MCQ (Single Correct) +4 −1
If the frequency of the dominant allele (p) in a population is 0.7, what is the frequency of the heterozygous genotype (Aa) according to the Hardy-Weinberg equilibrium?
  • Hardy-Weinberg Formula:
  • For a diallelic locus with alleles $A$ and $a$:
$$p + q = 1$$ $$p^2 + 2pq + q^2 = 1$$
  • Calculation:
  • Given dominant allele frequency: $p = 0.7$
  • Recessive allele frequency:
$$q = 1 - p = 1 - 0.7 = 0.3$$
  • Frequency of heterozygous genotype ($Aa$):
$$2pq = 2 \times 0.7 \times 0.3 = 0.42$$
  • nalysis:
  • (0.42): Correct.
  • (0.21): Represents $pq$ without multiplying by 2.
  • (0.49): Represents homozygous dominant frequency ($p^2 = 0.7^2$).

Correct option: (2) 0.42

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