• Mutation Equilibrium Calculation:
• Forward mutation rate ($A \rightarrow a$): $u = \frac{1}{10,000} = 10^{-4} = 0.0001$
• Backward mutation rate ($a \rightarrow A$): $v = \frac{1}{100,000} = 10^{-5} = 0.00001$
• Equilibrium Allele Frequencies:

$$\hat{q} = \frac{u}{u + v} = \frac{10^{-4}}{10^{-4} + 10^{-5}} = \frac{10}{11} \approx 0.9091$$ $$\hat{p} = 1 - \hat{q} = \frac{1}{11} \approx 0.0909$$

• Hardy-Weinberg Genotype Frequencies:

$$\text{Frequency of } AA = p^2 = (0.0909)^2 \approx 0.0083$$ $$\text{Frequency of } Aa = 2pq = 2 \times 0.0909 \times 0.9091 \approx 0.1653$$ $$\text{Frequency of } aa = q^2 = (0.9091)^2 \approx 0.8264$$

• Conclusion: Genotype frequencies are AA: 0.0083; Aa: 0.1653; aa: 0.8264. (Correct answer: Option 1)