Q.75
Genetics & Plant Breeding - ICAR JRF/SRF 2024
MCQ (Single Correct)
A predominantly self-fertiizing plant regularly cross-pollinates with a frequency of 3%. Assuming no selection, what will be the percent of heterozygotes at a locus with two alleles showing gene frequencies of 0.3 and 0.7?
  • Equilibrium Heterozygosity under Partial Selfing:
  • Outcrossing rate: $t = 0.03$ (3%), selfing rate: $s = 1 - t = 0.97$.
  • Allele frequencies: $p = 0.3, q = 0.7 \implies 2pq = 2 \times 0.3 \times 0.7 = 0.42$.
  • Inbreeding coefficient at mating equilibrium:
$$F = \frac{1 - t}{1 + t} = \frac{0.97}{1.03} \approx 0.9417$$
  • Frequency of heterozygotes:
$$H = 2pq(1 - F) = 2pq \left(\frac{2t}{1 + t}\right) = 0.42 \times \frac{0.06}{1.03} \approx 0.0245 = 2.45\%$$
  • Option Representation: Option 2 represents the corresponding equilibrium percentage. (Correct answer: Option 2)
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