• Hydraulic Jump Sequent Depth Calculation:
• Bélanger's Momentum Equation:

$$y_2 = \frac{y_1}{2} \left(\sqrt{1 + 8 Fr_1^2} - 1\right)$$

• Parameters:
• Channel width $B = 1\text{ m}$, Discharge $Q = 3.132\text{ m}^3\text{/s} \implies q = Q/B = 3.132\text{ m}^2\text{/s}$.
• Initial depth $y_1 = 0.8\text{ m}$.
• Initial velocity $v_1 = \frac{q}{y_1} = \frac{3.132}{0.8} = 3.915\text{ m/s}$.
• Initial Froude number:

$$Fr_1 = \frac{v_1}{\sqrt{g y_1}} = \frac{3.915}{\sqrt{9.81 \times 0.8}} = \frac{3.915}{\sqrt{7.848}} = \frac{3.915}{2.8014} = 1.3975$$ $$Fr_1^2 = (1.3975)^2 \approx 1.953$$

• Post-Jump Depth ($y_2$):

$$y_2 = \frac{0.8}{2}\left(\sqrt{1 + 8(1.953)} - 1\right) = 0.4 \times (\sqrt{16.624} - 1) = 0.4 \times (4.077 - 1) = 0.4 \times 3.077 \approx 1.23\text{ m}$$

• Conclusion: Depth of water after jump is 1.23 m (Option 1).

Correct option: (1) 23m