73
ICAR JRF 29 Jun 2024Shift 1
MCQ (Single Correct) +4 −1
Only 1% of the incident lights are transmitted in a pectin solution. What will be the absorbance value?
  • Beer-Lambert Law & Absorbance Calculation:
  • Formula:
$$A = -\log_{10}(T) = \log_{10}\left(\frac{I_0}{I}\right) = \log_{10}\left(\frac{100}{\%T}\right)$$

where $A$ is absorbance (optical density) and $T$ is fractional transmittance.

  • Calculation:
  • Transmittance $\%T = 1\% \implies T = 0.01$.
$$A = -\log_{10}(0.01) = -\log_{10}(10^{-2}) = -(-2) = 2$$
  • Conclusion: Absorbance value is 2 (Option 4).

Correct option: (4) 2

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