94
ICAR JRF 29 Jun 2024Shift 1
MCQ (Single Correct) +4 −1
Ashaft runs at 60 rpm and drives another shaft at 170 rpm through belt drive, neglecting the slip; what would be the velocity ratio
  • Velocity Ratio of Belt Drive Transmission:
  • Formula:
$$\text{Velocity Ratio} = \frac{N_2}{N_1} = \frac{\text{Speed of Driven Shaft}}{\text{Speed of Driving Shaft}}$$
  • Calculation:
  • Driving shaft speed ($N_1$) = $60\text{ rpm}$
  • Driven shaft speed ($N_2$) = $170\text{ rpm}$
$$\text{Velocity Ratio} = \frac{170}{60} = \frac{17}{6}$$
  • Conclusion: Velocity ratio is 17/6 (Option 2).

Correct option: (2) 1716

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