According to Newton's Law of Cooling for convective heat transfer:
\[ Q = h \cdot A \cdot (T_s - T_\infty) \]
Given parameters:
Heat transfer coefficient,
\(h = 30\text{ W}/(\text{m}^2\cdot{}^\circ\text{C})\) Surface area, \(A = 2\text{ m}^2\) Plate surface temperature, \(T_s = 40^\circ\text{C}\) Fluid (air) temperature, \(T_\infty = 10^\circ\text{C}\) Calculation: \[ Q = 30 \times 2 \times (40 - 10) = 60 \times 30 = 1800\text{ W} \]
Converting to kilowatts:
\[ Q = \frac{1800}{1000} = 1.8\text{ kW} \]
Thus, the heat flow rate is 1.8 kW.
न्यूटन के शीतलन नियम के अनुसार संवहन ऊष्मा अंतरण:
\(Q = h \cdot A \cdot \Delta T\) \(Q = 30 \times 2 \times (40 - 10) = 1800\text{ वाट} = 1.8\text{ kW}\)।
अतः ऊष्मा प्रवाह की दर 1.8 kW है।