Q.7
ICAR AIEEA PG Plant Biotechnology 14 July 2023 Shift-1 Paper (Q.12)
MCQ (Single Correct) +4 −1
The absorbance of a solution of an analyte having 75% transmittance would be equal to (Given: $\log 5 = 0.6990$ and $\log 3 = 0.4771$):
75% पारगम्यता वाले विश्लेष्य के विलयन का अवशोषण किसके बराबर होगा (दिया गया है: $\log 5 = 0.6990$ और $\log 3 = 0.4771$):

Relationship between Absorbance ($A$) and percentage Transmittance ($\%T$):

$$A = 2 - \log(\%T)$$

Given $\%T = 75\%$:

$$\log(75) = \log(3 \times 25) = \log 3 + 2\log 5 = 0.4771 + 2(0.6990) = 0.4771 + 1.3980 = 1.8751$$ $$A = 2 - 1.8751 = 0.1249 \approx 0.125$$
Therefore, the absorbance is approximately 0.125.

अवशोषण ($A$) और प्रतिशत पारगम्यता ($\%T$) के बीच संबंध:

$$A = 2 - \log(\%T)$$

यहाँ $\%T = 75\%$ दिया गया है:

$$\log 75 = \log(3 \times 5^2) = \log 3 + 2\log 5 = 0.4771 + 2(0.6990) = 0.4771 + 1.3980 = 1.8751$$ $$A = 2 - 1.8751 = 0.1249 \approx 0.125$$
अतः विलयन का अवशोषण $0.125$ है।
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