Calculation of average stream flow rate:
1. Watershed Area \(A = 600\text{ ha} = 600 \times 10,000\text{ m}^2 = 6 \times 10^6\text{ m}^2\). 2. Rainfall depth \(P = 10\text{ cm} = 0.10\text{ m}\). 3. Runoff/Rainfall ratio \(C = 0.2\). Runoff depth \(R = C \times P = 0.2 \times 0.10\text{ m} = 0.02\text{ m}\). 4. Total runoff volume \(V = A \times R = (6 \times 10^6\text{ m}^2) \times 0.02\text{ m} = 120,000\text{ m}^3\). 5. Flow duration \(t = 10\text{ hours} = 600\text{ minutes}\). 6. Average stream flow rate: - In \(\text{m}^3/\text{h}\): \(\frac{120,000\text{ m}^3}{10\text{ h}} = 12,000\text{ m}^3/\text{h}\).
- In \(\text{m}^3/\text{minute}\): \(\frac{120,000\text{ m}^3}{600\text{ min}} = 200\text{ m}^3/\text{minute}\). - In \(\text{m}^3/\text{s}\): \(\frac{120,000\text{ m}^3}{36,000\text{ s}} = 3.33\text{ m}^3/\text{s}\).
गणना:
- क्षेत्रफल \(A = 600\text{ ha} = 6,000,000\text{ m}^2\)
- वर्षा \(P = 10\text{ cm} = 0.1\text{ m}\)
- अपवाह गहराई \(R = 0.2 \times 0.1\text{ m} = 0.02\text{ m}\) 4. कुल अपवाह आयतन \(V = 6,000,000 \times 0.02 = 120,000\text{ m}^3\) 5. अवधि \(t = 10\) घंटे \(= 600\) मिनट 6. औसत प्रवाह दर \(Q = \frac{120,000\text{ m}^3}{600\text{ min}} = 200\text{ m}^3/\text{मिनट}\)।