Dual Nature of Matter and Radiation

The photoelectric current is directly proportional to the number of photoelectrons emitted per second. This implies that:

The de-Broglie wavelength associated with a ball of mass $150\,\text{g}$ traveling at $30.0\,\text{m/s}$ would be:

A proton accelerated through a potential difference of $V$ volts has a de-Broglie wavelength $\lambda$ associated with it. In order to get the same wavelength associated with an $\alpha$-particle, the required accelerating potential is:

Radiation of frequency $2\nu_0$ is incident on a metal with threshold frequency $\nu_0$. The correct statement of the following is ___________________.

A point source causing photoelectric emission from a metallic plate is moved away from the plate. The variation of photoelectric current with distance $d$ from the source is correctly represented by a curve where current drops inversely as the square of distance ($i \propto 1/d^2$) (Option 3).

A proton accelerated through a potential difference $V$ has a de Broglie wavelength $\lambda$. On doubling the accelerating potential, the de Broglie wavelength of the proton ____________________________.

A proton, a deuteron, an electron and an $\alpha$-particle have the same kinetic energy. Their de Broglie wavelengths are $\lambda_p, \lambda_d, \lambda_e$ and $\lambda_\alpha$ respectively. The correct arrangement in increasing order is:

The correct curve between stopping potential ($V_0$) and intensity of incident radiation ($I$) at constant frequency is:

Which of the following statements are correct?

Choose the correct answer from the options given below:

Number of photoelectrons emitted per second is proportional to :

Emission of electron from the surface of metal when radiation of appropriate frequency is allowed to incident on it is called :

An electron, an $\alpha$ particle, a proton and a deuteron have the same kinetic energy. Which of these particles has the shortest De Broglie wavelength :