In single slit diffraction, the diffraction angle $\theta = \frac{\pi}{3} = 60^\circ$.
Using the diffraction relation $e \sin\theta = \lambda$:
$$e \sin\left(\frac{\pi}{3}\right) = \lambda$$
$$e \left(\frac{\sqrt{3}}{2}\right) = \lambda \implies e = \frac{2}{\sqrt{3}}\lambda$$
Hence, option 1 is the correct answer.
एकल झिरी विवर्तन में विवर्तन कोण $\theta = \frac{\pi}{3} = 60^\circ$ है।
विवर्तन संबंध $e \sin\theta = \lambda$ का उपयोग करने पर:
$$e \sin\left(\frac{\pi}{3}\right) = \lambda$$
$$e \left(\frac{\sqrt{3}}{2}\right) = \lambda \implies e = \frac{2}{\sqrt{3}}\lambda$$
अतः विकल्प 1 सही उत्तर है।