Analysis of the statements according to electromagnetic theory:

• Statement I is true: Electrostatic field $\vec{E}$ is produced by electric charge $q$, which is a scalar quantity obeying Coulomb's law: $d\vec{E} = \frac{1}{4\pi\varepsilon_0}\frac{dq}{r^2}\hat{r}$.
• Statement II is true: Magnetic field $\vec{B}$ is produced by a current element $I\,d\vec{l}$, which is intrinsically a vector quantity obeying the Biot-Savart law: $d\vec{B} = \frac{\mu_0}{4\pi}\frac{I(d\vec{l} \times \hat{r})}{r^2}$.

• Step 1: Calculate electric field amplitude $E_0$:
  $$E_0 = c B_0 = (3 \times 10^8\,\text{m/s}) \times (2 \times 10^{-7}\,\text{T}) = 60\,\text{V/m}$$
• Step 2: Determine polarization direction:
  • The phase is $(ky + \omega t)$, which means the wave propagates along the negative $y$-axis ($-\hat{j}$).

• The magnetic field is along the $z$-axis ($\hat{k}$).
• Poynting vector gives the propagation direction: $\hat{S} = \hat{E} \times \hat{B} = -\hat{j}$.
• Since $\hat{i} \times \hat{k} = -\hat{j}$, the electric field vector $\vec{E}$ must be along the positive $x$-axis ($\hat{i}$).

According to Einstein's photoelectric theory:

• Each incident photon of frequency above the threshold frequency ($f \gt f_0$) can eject at most one photoelectron.
• The intensity of radiation is the number of incident photons striking unit area per second ($I = n h f$).