Q.78
ICAR AIEEA PG 2024 - Plant Sciences
Statement Based +4 −1

Given below are two statements

Statement (I) : The first amino acid in protein synthesis is Methionine in Eubacteria.
Statement (II) : The first amino acid in protein synthesis is N-formyl-methionine in Archaea.

In light of the above statements, choose the most appropriate answer from the options given below:

नीचे दो कथन दिए गए हैं

कथन (I) : यूबैक्टीरिया (Eubacteria) में प्रोटीन संश्लेषण में पहला अमीनो अम्ल मेथियोनीन (Methionine) होता है।
कथन (II) : आर्किया (Archaea) में प्रोटीन संश्लेषण में पहला अमीनो अम्ल N-फॉर्मिल-मेथियोनीन (fMet) होता है।

उपरोक्त कथनों के आलोक में, नीचे दिए गए विकल्पों में से सबसे उपयुक्त उत्तर चुनिए:

Initiator Amino Acid in Protein Translation:

  • In Eubacteria (True Bacteria): Translation initiates with a specialized modified amino acid, N-formylmethionine (fMet), delivered by initiator $\text{tRNA}_f^{\text{Met}}$.
  • In Archaea (and Eukaryotes): Translation initiates with unmodified Methionine (Met), carried by initiator $\text{tRNA}_i^{\text{Met}}$.
  • Comparison with the Statements:
  • Statement (I) erroneously claims Methionine initiates in Eubacteria (False, it is fMet).
  • Statement (II) erroneously claims N-formylmethionine initiates in Archaea (False, it is unmodified Met).
Therefore, both Statement (I) and Statement (II) are FALSE. Correct Answer: Option 2.

विस्तृत व्याख्या:

Initiator Amino Acid in Protein Translation (प्रोटीन अनुवाद में प्रारंभिक अमीनो अम्ल):

  • In Eubacteria (True Bacteria): Translation initiates with a specialized modified amino acid, N-formylmethionine (fMet), delivered by initiator $\text{tRNA}_f^{\text{Met}}$.
  • In Archaea (and Eukaryotes): Translation initiates with unmodified Methionine (Met), carried by initiator $\text{tRNA}_i^{\text{Met}}$.
  • Comparison with the Statements:
  • Statement (I) erroneously claims Methionine initiates in Eubacteria (False, it is fMet).
  • Statement (II) erroneously claims N-formylmethionine initiates in Archaea (False, it is unmodified Met).
Therefore, both Statement (I) and Statement (II) are FALSE. Correct Answer: Option 2.
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