- Step 1: Cross-Sectional Area of Orifice ($A$):
$$d = 0.07\text{ m} \implies A = \frac{\pi d^2}{4} = \frac{\pi (0.07)^2}{4} \approx 0.0038485\text{ m}^2$$
- Step 2: Difference in Head ($H$) and Velocity ($v$):
$$H = 19.62\text{ cm} = 0.1962\text{ m}$$
$$v = \sqrt{2gH} = \sqrt{2 \times 9.81 \times 0.1962} = \sqrt{19.62 \times 0.1962} = 1.962\text{ m/s}$$
- Step 3: Discharge Rate ($Q$):
$$Q = C_d \cdot A \cdot v \approx 0.61 \times 0.0038485 \times 1.962 \approx 0.0046078\text{ m}^3/\text{s}$$
- Step 4: Total Time in Seconds ($t$):
$$t = 2\text{ h } 46\text{ min } 40\text{ s} = 7200 + 2760 + 40 = 10,000\text{ s}$$
- Step 5: Total Volume in Lakh Litres:
$$\text{Volume} = 0.0046078\text{ m}^3/\text{s} \times 10,000\text{ s} = 46.078\text{ m}^3 = 46,078\text{ Litres}$$
$$\text{Total in Lakh Litres} = \frac{46,078}{100,000} = 0.46078\text{ lakh litres}$$
- Conclusion: Total discharge is 0.46078 lakh litres. (Correct answer: Option 4)