Q100: In a population in Hardy-Weinberg equilibrium, if the frequency of... - Cell Biology, Genetics, Physiology, Biochemistry & Plant Protection - ICAR AIEEA PG 2024 - Plant Sciences | Agrigyan

विस्तृत व्याख्या:

Hardy-Weinberg Law of Population Genetics (हार्डी-वीनबर्ग समीकरण):

• In a large, randomly mating population free from selection, mutation, and migration:

where:

• $p$ = frequency of the dominant allele ($A$)
• $q$ = frequency of the recessive allele ($a$)
• $p^2$ = frequency of homozygous dominant genotype ($AA$)
• $2pq$ = frequency of heterozygous genotype ($Aa$)
• $q^2$ = frequency of homozygous recessive genotype ($aa$)
• Calculation:
• Given: Frequency of $AA = p^2 = 0.64$
• Frequency of dominant allele $A = p = \sqrt{p^2} = \sqrt{0.64} = 0.8$