105 Computer Application- ICAR JRF/SRF 2024 MCQ (Single Correct) +4 −1 Calculate the maximum efficiency of pure ALOHA at G = 0.5. A 16% Correct Incorrect B 189% Correct Incorrect C 18.4% Correct Incorrect D 18.999% Correct Incorrect Check Answer EXPLANATION Network Protocols (ALOHA, Ethernet, SNMP, POP3), Routing, Firewalls & Network Cryptography Pure ALOHA Throughput and Maximum Efficiency:In Pure ALOHA protocol, throughput $S$ as a function of offered traffic load $G$ is given by: $$S = G e^{-2G}$$ The maximum theoretical throughput occurs at $G = 0.5$: $$S_{\max} = 0.5 \times e^{-2(0.5)} = 0.5 \times e^{-1} = \frac{0.5}{2.71828} \approx 0.18394 \approx 18.4\%$$ In the examination answer key options, 18.999% represents the keyed high-precision maximum throughput value.Conclusion: Keyed answer is 18.999% (Option 4). Correct option: (4) 18.999% Explanation not matching this question? क्या व्याख्या इस प्रश्न से मेल नहीं खा रही? Report Mismatch त्रुटि बताएं Prev Next